Optimal. Leaf size=67 \[ \frac {(d x)^{m+1} \left (a+b \text {csch}^{-1}(c x)\right )}{d (m+1)}+\frac {b (d x)^m \, _2F_1\left (\frac {1}{2},-\frac {m}{2};1-\frac {m}{2};-\frac {1}{c^2 x^2}\right )}{c m (m+1)} \]
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Rubi [A] time = 0.05, antiderivative size = 67, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {6284, 339, 364} \[ \frac {(d x)^{m+1} \left (a+b \text {csch}^{-1}(c x)\right )}{d (m+1)}+\frac {b (d x)^m \, _2F_1\left (\frac {1}{2},-\frac {m}{2};1-\frac {m}{2};-\frac {1}{c^2 x^2}\right )}{c m (m+1)} \]
Antiderivative was successfully verified.
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Rule 339
Rule 364
Rule 6284
Rubi steps
\begin {align*} \int (d x)^m \left (a+b \text {csch}^{-1}(c x)\right ) \, dx &=\frac {(d x)^{1+m} \left (a+b \text {csch}^{-1}(c x)\right )}{d (1+m)}+\frac {(b d) \int \frac {(d x)^{-1+m}}{\sqrt {1+\frac {1}{c^2 x^2}}} \, dx}{c (1+m)}\\ &=\frac {(d x)^{1+m} \left (a+b \text {csch}^{-1}(c x)\right )}{d (1+m)}-\frac {\left (b \left (\frac {1}{x}\right )^m (d x)^m\right ) \operatorname {Subst}\left (\int \frac {x^{-1-m}}{\sqrt {1+\frac {x^2}{c^2}}} \, dx,x,\frac {1}{x}\right )}{c (1+m)}\\ &=\frac {(d x)^{1+m} \left (a+b \text {csch}^{-1}(c x)\right )}{d (1+m)}+\frac {b (d x)^m \, _2F_1\left (\frac {1}{2},-\frac {m}{2};1-\frac {m}{2};-\frac {1}{c^2 x^2}\right )}{c m (1+m)}\\ \end {align*}
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Mathematica [A] time = 0.24, size = 81, normalized size = 1.21 \[ \frac {x (d x)^m \left ((m+1) \left (a+b \text {csch}^{-1}(c x)\right )+\frac {b c x \sqrt {\frac {1}{c^2 x^2}+1} \, _2F_1\left (\frac {1}{2},\frac {m+1}{2};\frac {m+3}{2};-c^2 x^2\right )}{\sqrt {c^2 x^2+1}}\right )}{(m+1)^2} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.83, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (b \operatorname {arcsch}\left (c x\right ) + a\right )} \left (d x\right )^{m}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b \operatorname {arcsch}\left (c x\right ) + a\right )} \left (d x\right )^{m}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.05, size = 0, normalized size = 0.00 \[ \int \left (d x \right )^{m} \left (a +b \,\mathrm {arccsch}\left (c x \right )\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ {\left (c^{2} d^{m} \int \frac {x^{2} x^{m}}{c^{2} {\left (m + 1\right )} x^{2} + {\left (c^{2} {\left (m + 1\right )} x^{2} + m + 1\right )} \sqrt {c^{2} x^{2} + 1} + m + 1}\,{d x} - \frac {d^{m} x x^{m} \log \relax (x) - d^{m} x x^{m} \log \left (\sqrt {c^{2} x^{2} + 1} + 1\right )}{m + 1} - \int \frac {{\left (c^{2} d^{m} {\left (m + 1\right )} x^{2} \log \relax (c) + d^{m} {\left (m + 1\right )} \log \relax (c) - d^{m}\right )} x^{m}}{c^{2} {\left (m + 1\right )} x^{2} + m + 1}\,{d x}\right )} b + \frac {\left (d x\right )^{m + 1} a}{d {\left (m + 1\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int {\left (d\,x\right )}^m\,\left (a+b\,\mathrm {asinh}\left (\frac {1}{c\,x}\right )\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (d x\right )^{m} \left (a + b \operatorname {acsch}{\left (c x \right )}\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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